Source code for annotations.TextNorm.num2text.num_khm
# -*- coding: UTF-8 -*-
"""
..
---------------------------------------------------------------------
___ __ __ __ ___
/ | \ | \ | \ / the automatic
\__ |__/ |__/ |___| \__ annotation and
\ | | | | \ analysis
___/ | | | | ___/ of speech
http://www.sppas.org/
Use of this software is governed by the GNU Public License, version 3.
SPPAS is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
SPPAS is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with SPPAS. If not, see <http://www.gnu.org/licenses/>.
This banner notice must not be removed.
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"""
from .num_europ_lang import sppasNumEuropeanType
# ---------------------------------------------------------------------------
[docs]class sppasNumKhmer(sppasNumEuropeanType):
"""Return an instance of sppasNumKhmer
:retruns: (sppasNumKhmer)
"""
[docs] def __init__(self, dictionary):
sppasNumEuropeanType.NUMBER_LIST = (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10,
20, 30, 40, 50, 60, 70, 80, 90,
100, 1000, 10000, 100000)
super(sppasNumKhmer, self).__init__('khm', dictionary)
self.separator = ''
# ---------------------------------------------------------------------------
def _hundreds_of_thousands(self, number):
"""Return the "wordified" version of a hundred of a thousand number
Returns the word corresponding to the given hundred of a thousand number
within the current language dictionary
:param number: (int) number to convert in word
:returns: (str)
"""
if number < 100000:
return self._thousands(number)
else:
mult = None
if int(number / 10000) * 10000 != 10000:
mult = self._thousands(int(number / 10000))
if mult is None:
if int(str(number)[1:]) == 0:
return self._lang_dict['1'] \
+ self._lang_dict['100000']
else:
return self._lang_dict['1'] \
+ self._lang_dict['100000'] \
+ self._thousands(number % 10000)
else:
if int(str(number)[1:]) == 0:
return mult + self._lang_dict['100000']
else:
return mult + self._lang_dict['100000'] \
+ self._thousands(number % 10000)
# ---------------------------------------------------------------------------
def _millions(self, number):
if number < 1000000:
return self._hundreds_of_thousands(number)
elif number > 1000000000:
return None
else:
mult = None
if int(number / 1000000) * 1000000 != 1000000:
mult = self._hundreds_of_thousands(int(number / 1000000))
if mult is None:
if int(str(number)[1:]) == 0:
return self._lang_dict['1'] + self.separator \
+ self._lang_dict['1000000']
else:
return self._lang_dict['1'] + self.separator \
+ self._lang_dict['1000000'] \
+ self.separator \
+ self._hundreds_of_thousands(number % 1000000)
else:
if int(str(number)[1:]) == 0:
return mult + self.separator \
+ self._lang_dict['1000000']
else:
return mult + self.separator \
+ self._lang_dict['1000000'] \
+ self.separator \
+ self._hundreds_of_thousands(number % 1000000)
# ---------------------------------------------------------------------------
def _billions(self, number):
"""Return the "wordified" version of a billion number
Returns the word corresponding to the given billion number within the
current language dictionary
:param number: (int) number to convert in word
:returns: (str)
"""
if number < 1000000000:
return self._millions(number)
elif number > 1000000000000:
return None
else:
mult = None
if int(number / 1000000000) * 1000000000 != 1000000000:
mult = self._millions(int(number / 1000000000))
if mult is None:
if int(str(number)[1:]) == 0:
return self._lang_dict['1'] + self.separator \
+ self._lang_dict['1000000000']
else:
return self._lang_dict['1'] + self.separator \
+ self._lang_dict['1000000000'] \
+ self.separator \
+ self._millions(number % 1000000000)
else:
if int(str(number)[1:]) == 0:
return mult + self.separator \
+ self._lang_dict['1000000000']
else:
return mult + self.separator \
+ self._lang_dict['1000000000'] \
+ self.separator \
+ self._millions(number % 1000000000)